You just have to calculate the R-value of materials:

$$ R = \frac{e}{\lambda}$$

Where:

• $R$: Thermal Resistance ($m^2 \cdot K \cdot W^{-1}$)
• $e$: Thickness ($m$)
• $\lambda$: Conductivity ($W \cdot m^{-1} \cdot K^{-1}$)

So your insulation layer is wall_consol_layer:

You just have to calculate the R-value of materials:

$$ R = \frac{e}{\lambda}$$

Where:

• $R$: Thermal Resistance ($m^2 \cdot K \cdot W^{-1}$)
• $e$: Thickness ($m$)
• $\lambda$: Conductivity ($W \cdot m^{-1} \cdot K^{-1}$)

So your insulation layer is wall_consol_layer:

$$ R = \frac{e}{\lambda}$$

Where:

• $R$: Thermal Resistance ($m^2 \cdot K \cdot W^{-1}$)
• $e$: Thickness ($m$)
• $\lambda$: Conductivity ($W \cdot m^{-1} \cdot K^{-1}$)

So your insulation layer is wall_consol_layer:

| Material | Material | Material | | |------------------------|------------------------|-------------------|-------------------| | Name | sheathing_consol_layer | OSB_5/8in | wall_consol_layer | | Roughness | Rough | MediumSmooth | Rough | | Thickness (m) | 0.0127 | 0.015875032180756 | 0.1397 | | Conductivity | 0.0940184 | 0.1163 | 0.05966275 | | Density (kg/m3) | 685.008 | 544.627399310259 | 120.801 | | Specific Heat (J/kg.K) | 1172.332 | 1213.36000918149 | 1036.25775 | | R-value | 0.14 | 0.14 | 2.34 |